问题：

get('module-'.SITE_ID.'-content'); foreach ($rt as $key => $value) { $module[] = $key; } $mod = implode(",",$module); var_dump ($mod); ?>

循环多个模块，以上运行结果输出模块名称 news,jsmk,zjmk

想要排除news模块，用unset($key['news']);

get('module-'.SITE_ID.'-content'); foreach ($rt as $key => $value) { unset($key['news']); //排除news $module[] = $key; } $mod = implode(",",$module); var_dump ($mod); ?>

但是报错，应该怎么修改下，才能排除news模块呢？

答案：

get('module-'.SITE_ID.'-content'); foreach ($rt as $key => $value) { if ($key != 'news') {  $module[] = $key; } } $mod = implode(",",$module); var_dump ($mod);?>

补习一下php知识

@迅睿框架联合创始人：感谢，好用。